Question

In case of a circular section the section modulus is given as

• A. $$\pi d ^ 3 / 16$$
• B. $$\pi d ^ 3 / 8$$
• C. $$\pi d ^ 3 / 32$$
• D. $$\pi d ^ 3 / 64$$

Answer 1

Answer:

$$\pi d ^ 3 / 32$$

The sectional modulus of a circular section is given by the ratio of moment of inertia to the distance of extreme fiber from the neutral axis. For a circular section, the equation is $Z = \pi d ^ 3 / 32$ where d is the diameter of the circle.