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A high-end watch is initially marked up by 50% above its cost price. During a sale, it is offered at a discount of 20% on its marked price. However, a special customer receives an additional discount of y% on the discounted price, bringing the final selling price to ₹4320. If the shopkeeper still makes a profit of 8% on the cost price after all discounts, what was the original cost price of the watch and the value of y?

ACP = ₹4000 , y = 10%

BCP = ₹4500 , y = 10%

CCP = ₹4800 , y = 5%

DCP = ₹5000 , y = 8%

Answer:

A. CP = ₹4000 , y = 10%

Read Explanation:

Let the cost price (CP) of the watch be (x).

Step 1: Marked Price (MP)

The watch is marked up by 50%:

MP = 1.5x

Step 2: After 20% discount

Selling price after the first discount:


=1.5x×0.8=1.2x= 1.5x \times 0.8 = 1.2x

Step 3: After additional (y%) discount

Final selling price is ₹4320:

1.2x(1−y100)=43201.2x\left(1-\frac{y}{100}\right)=4320

Step 4: Use the profit condition

The shopkeeper still earns 8% profit:


SP = 1.08x

Since the final SP is ₹4320,


1.08x=4320

x=43201.08=4000x=\frac{4320}{1.08}=4000

So, the original cost price = ₹4000.

Step 5: Find (y)

Substitute (x=4000):


1.2(4000)(1−y100)=43201.2(4000)\left(1-\frac{y}{100}\right)=4320

4800(1−y100)=43204800\left(1-\frac{y}{100}\right)=4320

1−y100=43204800=0.91-\frac{y}{100}=\frac{4320}{4800}=0.9

y100=0.1\frac{y}{100}=0.1

y=10%\boxed{y=10\%}

Final Answer

  • Original Cost Price = ₹4000

  • AdditionalDiscount=(10%)Additional Discount = (\boxed{10\%})


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