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A man goes to Ahmedabad from Kolkata at a speed of 78km/hr and returns to Kolkata at speed of 91km/hr, through same route. What is his average speed (in km/hr) of the entire journey?

A78

B81

C84

D85

Answer:

C. 84

Read Explanation:

Since the distance is the same both ways, we use the average speed formula for equal distances:

Average speed=2aba+b\text{Average speed} = \frac{2ab}{a+b}

where
(a = 78) km/hr and (b = 91) km/hr.

Average speed=2×78×9178+91\text{Average speed} = \frac{2 \times 78 \times 91}{78 + 91}
=14196169= \frac{14196}{169}
=84 km/hr= 84 \text{ km/hr}
Average speed of the entire journey = 84 km/hr


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