A man travelled at a speed of 20m/min for 100 min, and at a speed of 70m/min for 50 min. His average speed isA35 m/minB703m/min\frac{70}{3}m/min370m/minC25 m/minD1103m/min\frac{110}{3} m/min3110m/minAnswer: 1103m/min\frac{110}{3} m/min3110m/min Read Explanation: Speed S1 = 20 m/minTime T1= 100minS2=70 m/minT2=50 minAverage speed = 20×100+70×50100+50\frac{20\times{100}+70\times{50}}{100+50}100+5020×100+70×50=2000+3500150=\frac{2000+3500}{150}=1502000+3500=5500150=\frac{5500}{150}=1505500=1103m/min=\frac{110}{3} m/min=3110m/min Read more in App