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A person divides his total journey into three equal parts and decides to travel the three parts with the speeds of 40, x and 15 km/h, respectively. If his average speed during the whole journey is 24 km/h, then find the value of x.

A30 km/h

B38 km/h

C32 km/h

D35 km/h

Answer:

A. 30 km/h

Read Explanation:

Solution:

Given:

A person divides his journey into three equal parts and travels three parts with speeds of 40 km/h, X km/h, and 15 km/h

Average speed for the whole journey = 24 km/h

Formula Used:

Average Speed =D1+D2+D3+....+DnD1S1+D2S2+D3S3+....+DnSn=\frac{D1+D2+D3+....+Dn}{\frac{D1}{S1}+\frac{D2}{S2}+\frac{D3}{S3}+....+\frac{Dn}{Sn}}

Where D1, D2, D3, Dn are distances and S1, S2, S3, Sn are respective speeds

Calculation:

Let the total distance of the journey be 360 km (120 + 120 + 120)

According to the question

24=120+120+12012040+120x+1201524=\frac{120+120+120}{\frac{120}{40}+\frac{120}{x}+\frac{120}{15}}

24=3603+8+120x24=\frac{360}{3+8+\frac{120}{x}}

24=36011+120x24=\frac{360}{11+\frac{120}{x}}

264+24×120x=360264+\frac{24\times 120}{x}=360

264(1+24×120x)=360264(1+\frac{24\times 120}{x})=360

24×120x=96\frac{24\times 120}{x}=96

x=24×12096=30km/hx=\frac{24\times 120}{96}=30km/h

The value of x is 30 km/h. 


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