A point on the y axis which is equi distant from (-2,5) and (2,-3) ?A(0,2)B(1,0)C(0,1)D(0,-1)Answer: C. (0,1) Read Explanation: Midpoint = (x1+x22,y1+y22)(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})(2x1+x2,2y1+y2)=(−2+22,5−32)=(0,1)=(\frac{-2+2}{2},\frac{5-3}{2})=(0,1)=(2−2+2,25−3)=(0,1) Read more in App