Question

In a circle with radius 5 cm, AG and CD are two diameters perpendicular to each other. The length of chord AC is:

• A. 4√2 cm
• B. 5√2 cm
• C. 5 cm
• D. 6√3 cm

Answer 1

Answer:

B. 5√2 cm

According to the question,

⇒ OA = OC = 5 cm

We can see that ΔAOC is a right triangle. [∵ ∠AOC = 90°]

Length of AC,

⇒ √(OA² + OC² )

⇒ √(5² + 5²)

⇒ 5√2 cm

∴ The length of AC is 5√2 cm.