A ring-shaped disc has outer radius 10 cm and inner radius 7 cm. What is the approximate ratio of the ring's area to the whole outer circle?A1 : 2B2 : 3C3 : 4D4 : 5Answer: A. 1 : 2 Read Explanation: Using (π=227)( \pi = \frac{22}{7} )(π=722):Ring areaRing area=π(102−72)=227(100−49)=227×51\text{Ring area} = \pi(10^2 - 7^2) = \frac{22}{7}(100 - 49) = \frac{22}{7} \times 51Ring area=π(102−72)=722(100−49)=722×51Outer circle areaOuter area=π×102=227×100\text{Outer area} = \pi \times 10^2 = \frac{22}{7} \times 100Outer area=π×102=722×100RatioRing areaOuter area=227×51227×100=51100\frac{\text{Ring area}}{\text{Outer area}} = \frac{\frac{22}{7} \times 51}{\frac{22}{7} \times 100} = \frac{51}{100}Outer areaRing area=722×100722×51=10051Approximation:51100=0.51≈0.5=12\frac{51}{100} = 0.51 \approx 0.5 = \frac{1}{2}10051=0.51≈0.5=21Final Answer:1:2 (approx)\boxed{1 : 2 \ (\text{approx})}1:2 (approx) Read more in App