App Logo

No.1 PSC Learning App

1M+ Downloads
A rod having a cross-sectional area of 100 x 10⁻⁶ m² is subjected to a tensile load. Based on the Tresca failure criterion, if the uniaxial yield stress of the material is 200 MPa, the failure load is:

A10 kN

B20 kN

C100 kN

D200 kN

Answer:

B. 20 kN

Read Explanation:

Given: C.S Area = 100×106m2100 \times 10 ^ {- 6} m ^ 2 = 100mm2100mm ^ 2 , Syt = 200 MPa; Since only one tensile load is acting, it will give rise to σ1\sigma_{1} whereas σ2,σ3=0\sigma_{2}, \sigma_{3} = 0 Syt2×FOS=max[σ1σ22,σ2σ32,σ3σ12]\frac{S_{yt}}{2 \times FOS}=| max[ \frac{\sigma_1-\sigma_2}{2},\frac{\sigma_2-\sigma_3}{2},\frac{\sigma_3-\sigma_1}{2}]|

[FOS=1]; syt2=σ12σ1=Sytσ1=200MPa\frac{s_{yt}}{2}=\frac{\sigma_1}{2}\Rightarrow\sigma_1=S_{yt}\Rightarrow \sigma_1=200 MPa and

σ1=LoadC.S.Area\sigma_1=\frac{Load}{C.S.Area} 200=Load100Load=2×104N=20kN\Rightarrow 200=\frac{Load}{100} \Rightarrow Load=2\times 10^4 N=20kN


Related Questions:

Von mises and Tresca criteria give different yield stress for
Guest's theory of failure is applicable for following type of materials
The maximum permissible twisting moment in a circular shaft, according to the maximum shear stress theory of failure, is 'T'. According to the maximum principal stress theory of failure, the permissible twisting moment for the same shaft is:
For proper design of a shaft, it should be designed on the basis of
A cold-rolled steel shaft is designed on the basis of the maximum shear stress theory. The Principal stresses induced at its critical section are 50 MPa and -50 MPa respectively. If the yield stress for the shaft material is 400 MPa, the factor of safety of the design is