Given: C.S Area = 100×10−6m2 = 100mm2 , Syt = 200 MPa; Since only one tensile load is acting, it will give rise to σ1 whereas σ2,σ3=0 2×FOSSyt=∣max[2σ1−σ2,2σ2−σ3,2σ3−σ1]∣
[FOS=1]; 2syt=2σ1⇒σ1=Syt⇒σ1=200MPa and
σ1=C.S.AreaLoad ⇒200=100Load⇒Load=2×104N=20kN