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A seamless pipe having a diameter of 600 mm and thickness of 9 mm, contain the fluid under a pressure of 4 MPa, find the longitudinal stress developed in the pipe.

A77.7 Mpa

B88.8 Mpa

C66.6 Mpa

D133.3 Mpa

Answer:

C. 66.6 Mpa

Read Explanation:

Given: p = 4MPa t = 9 mm and d = 600mm Longitudinal stress σl=Pd4tσl=4×6004×9=66.66MPa\sigma_{l} = \frac{Pd}{4t} \Rightarrow \sigma_{l} =\frac{4 \times 600}{4 \times 9} = 66.66MPa

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