Question

A thin cylinder of 'D' internal diameter, is subjected to an internal pressure of 'P'. If the permissible tensile stress is σt, the cylinder wall thickness should be

• A. $$\frac{2\sigma_{t}}{PD}$$
• B. $$\frac{PD}{\sigma_{t}}$$
• C. $$\frac{PD}{4\sigma_{t}}$$
• D. $$\frac{PD}{2\sigma_{t}}$$

Answer 1

Answer:

$$\frac{PD}{2\sigma_{t}}$$

A thin cylinder with internal diameter D and pressure P induces circumferential and longitudinal stresses, and radial compressive stress is neglected. The cylinder wall thickness is given by $t = (PD)/(2\sigma_{t})$ where sigma_{t} is the hoop stress.