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A sector of a circle having a radius of 10 cm and has a central angle of ⅚ radians. What is the area of the sector?

A26.18 cm²

B8.33 cm²

C10.47 cm²

D12.5 cm²

Answer:

A. 26.18 cm²

Read Explanation:

For a sector with radius (r) and central angle (\theta) in radians:

Area of sector=12r2θ\text{Area of sector}=\frac{1}{2}r^2\theta

Substitute (r=10) cm and (θ=π6):(\theta=\frac{\pi}{6}):


Area\text{Area}
=12(10)2(π6)=\frac{1}{2}(10)^2\left(\frac{\pi}{6}\right)


=100π12=\frac{100\pi}{12}


=25π3=\frac{25\pi}{3}

Area≈25×3.14163\text{Area} \approx \frac{25 \times 3.1416}{3}

≈26.18 cm2\approx 26.18 \text{ cm}^2

Answer:(25π3 cm2≈26.18 cm2). (\frac{25\pi}{3}\ \text{cm}^2 \approx 26.18\ \text{cm}^2).


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