Question

A solid round bar of 6 cm diameter is 2.5 m long. It is used as column with one end fixed and other end hinged. If elastic modulus is 200 GPa, the Euler's buckling load will be

• A. 804 kN
• B. 402 kN
• C. 201 kN
• D. None of the above

Answer 1

Answer:

B. 402 kN

Given: L = 2.5m = 2500mm d = 6cm = 60mm , $E =200\times 10 ^ 3 GPa$ $I ={\pi}{64} \times (60) ^ 4$ and For one end hinged and one end fixed, $L_{e} = L/\sqrt{2} = 2500/\sqrt2$ $P =\frac{\pi ^ 2 EI}{L_{e} ^ 2} = \frac{\pi ^ 2 \times 200 \times 10 ^ 3 \times \pi \times (60) ^ 4 \times (\sqrt(2)) ^ 2}{64 \times (2500) ^ 2} \Rightarrow P=401841.3$ $N=402 KN$