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A vendor wants to gain 25% by adding water to milk and selling the mixture at the cost price. Find the ratio of water and milk in the mixture.

A2 : 5

B1 : 4

C2 : 7

D1 : 5

Answer:

B. 1 : 4

Read Explanation:

Let the cost price of milk = ₹1 per unit.

Let water be free (cost = 0), and mixture is sold at cost price with 25% gain.

Selling condition

He sells mixture at CP but gains 25%, so:

Selling Price=125% of CP\text{Selling Price} = 125\% \text{ of CP}

So,
CP of mixture=100125=45\text{CP of mixture} = \frac{100}{125} = \frac{4}{5}

This means:

  • 1 unit mixture costs him ₹0.8

So milk portion must be 0.8 of mixture, rest is water.

Water and milk ratio

Milk in 1 unit mixture = 0.8
Water = 0.2

Milk : Water=0.8:0.2=4:1\text{Milk : Water} = 0.8 : 0.2 = 4 : 1

So reverse for water : milk:

Water : Milk=1:4\text{Water : Milk} = 1 : 4
Final Answer:

Water : Milk = 1 : 4


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