An element belongs to 3rd period. The (n + 1) value of its outer most subshell is 4. How many orientations are there for the given subshell?
A1
B3
C5
D7
Answer:
B. 3
Read Explanation:
• The problem states the element belongs to the 3rd period. Therefore, the principal quantum number for its outermost shell is n = 3
• We are given that the (n + l) value of the outermost subshell is 4
• .Using the value of n we just identified:3 + l = 4
• l = 4 - 3
• l = 1is the p subshell.
• the outermost subshell is 3p.