Question

An equilateral triangle of side 3cm has its corners cut-off to form a regular hexagon.What is the ratio of the areas of the two polygons

• A. 4:3
• B. 3:2
• C. 1:2
• D. 3:4

Answer 1

Answer:

B. 3:2

$\frac{\sqrt3a^2}{4}=\frac{9\sqrt3}{4}$

$\frac{6a^2\sqrt3}{4}=\frac{6\sqrt3}{4}$

$\frac{9\sqrt3/4}{6\sqrt3/4}=3/2$

$=3:2$