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At what rate per cent of compound interest will a sum of ₹2,000 amount to ₹4,394 in 3 years?

A25

B20

C30

D35

Answer:

C. 30

Read Explanation:

The required rate of compound interest is 30% per annum.

1. Identify Given Values

  • Principal (PP) = ₹2,000

  • Amount (AA) = ₹4,394

  • Time (nn) = 3 years

  • Rate (RR) = ?

2. Apply Compound Interest Formula

The standard formula for the total amount under compound interest is:
A=P(1+R100)nA = P \left(1 + \frac{R}{100}\right)^n

Substitute the given values into the formula:
4,394=2,000(1+R100)34,394 = 2,000 \left(1 + \frac{R}{100}\right)^3

3. Simplify the Ratio

Divide both sides by 2,000:
4,3942,000=(1+R100)3\frac{4,394}{2,000} = \left(1 + \frac{R}{100}\right)^3

Reduce the fraction to its simplest form by dividing the numerator and denominator by 2:
2,1971,000=(1+R100)3\frac{2,197}{1,000} = \left(1 + \frac{R}{100}\right)^3

4. Take the Cube Root

Recognize the perfect cubes on the left side (2,197=1332,197 = 13^3 and 1,000=1031,000 = 10^3):
(1310)3=(1+R100)3\left(\frac{13}{10}\right)^3 = \left(1 + \frac{R}{100}\right)^3

Take the cube root of both sides:
1310=1+R100\frac{13}{10} = 1 + \frac{R}{100}

5. Solve for R

Subtract 1 from both sides:
R100=1310−1\frac{R}{100} = \frac{13}{10} - 1

R100=310\frac{R}{100} = \frac{3}{10}

Multiply by 100:
R=310×100=30%R = \frac{3}{10} \times 100 = 30\%


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