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Calculate the circumferential stress on a thin-walled pressure tank that experiences an internal pressure of 4 MPa and external pressure of 2.5 MPa. The tank is 50 mm thick with a diameter of 200 mm.

A3 MPa

B30 MPa

C3×105Pa3 \times 10^5 Pa

D3×104Pa3 \times 10^4 Pa

Answer:

A. 3 MPa

Read Explanation:

Given: Pi=4MPaP_{i} = 4MPa Pe=2.5MPaP_{e} = 2.5MPa , t=50mmt = 50mm d=200mmd = 200mm. P=PiPe=42.5=1.5MPaP = P_{i} - P_{e} = 4 - 2.5 = 1.5MPa :: σc=Pd2t=σc=1.5×2002×50=3MPa\sigma_{c} =\frac{Pd}{2t}=\sigma_{c} = \frac{1.5 \times 200}{2 \times 50} = 3MPa

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