Question

What is the volumetric strain in the thin cylinder subjected to internal pressure having hoop stress of 200 MPa, modulus of elasticity, E = 200 GPa and Poisson's ratio = 0.25?

• A. 20/1000
• B. 2/1000
• C. 0.2/1000
• D. 0.02/1000

Answer 1

Answer:

B. 2/1000

Given: $\sigma_{h} = 200MPa$ $E = 200GPa = 200 \times 10 ^ 3 MPa$ $\mu = 0.25$ $\epsilon_{v} =\frac{\sigma_{h}}{E} [\frac 52 - 2\mu] =\frac{ 200}{200 \times 10 ^ 3} [\frac 52 - 2(0.25)] = \frac{2}{1000}$