Question

Calculate the value of shear stress (MPa) in the solid circular shaft of diameter 0.1 m which is subjected to the torque of 10 kN-m.

• A. 40.5
• B. 50.93
• C. 60.5
• D. 70.5

Answer 1

Answer:

B. 50.93

Given: T = 10kN - m = 10 x 1000Nm d = 0.1m Calculation:$\tau = T/J \times r$= $\frac {T}{\frac {\pi}{32} d ^ 4} \frac {d}{2} =\frac {16T}{\pi d ^ 3}$ $\tau =\frac{16 \times 10 ^ 4}{\pi (0.1) ^ 3}$= $50.93MPa$