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A18

B15

C12

D14

Answer:

$(3x-2y)^2(x^2+y^3)^2$

$(9x^2-12xy+4y^2)(x^4+2x^2y^3+y^6)$

coefficient of $x^4y^3$

$9x^2\times 2x^2y^3$

$18x^4y^3$

Related Questions:

The product of the roots of the quadratic equation $6-5x^2-8x = 0$ is:

6(x ^ 3 - 2x ^ 2 + 3x) - (x ^ 3 + 2x - 3)

Find the zero of the polynomial : $p(x)=2x^2+13x-7$