If a and b are the roots of x2+x−2=0x^2 + x - 2 = 0x2+x−2=0, then the quadratic equation in x whose roots are 1a+1b\frac1a + \frac1ba1+b1 and ab is: A2x2+3x−2=02x^2+3x-2=02x2+3x−2=0B2x2−5x−2=02x^2-5x-2=02x2−5x−2=0C2x2+5x−2=02x^2+5x-2=02x2+5x−2=0D2x2−3x+2=02x^2-3x+2=02x2−3x+2=0Answer: 2x2+3x−2=02x^2+3x-2=02x2+3x−2=0 Read Explanation: Conclusions II and III follow Read more in App