Divide 910 into three parts in such a way that one-third of the first part, one-fifth of the second part and one-sixth of the third part are equal. Then, the second part is

Challenger App

No.1 PSC Learning App

★

1M+ Downloads

Get App

Divide 910 into three parts in such a way that one-third of the first part, one-fifth of the second part and one-sixth of the third part are equal. Then, the second part is

A195

B325

C210

D390

Answer:

B. 325

Read Explanation:

(1/3) × A = (1/5) × B = (1/6) × C = x A = 3x, B = 5x C = 6x A + B + C = 910 ⇒ 3x + 5x + 6x = 910 ⇒ 14x = 910 ⇒ x = 65 Second part = 5x = 5 × 65 ⇒ 325

Read more in App

Related Questions:

Two numbers are, respectively, 17% and 50% more than a third number. The ratio of the two numbers is?.

Find the fourth proportional of 6, 24 and 11.

നാല് സംഖ്യകൾ യഥാക്രമം 3 : 1 : 7 : 5 എന്ന അനുപാതത്തിലാണ്. ഈ നാല് സംഖ്യകളുടെയും ആകെത്തുക 336 ആണെങ്കിൽ, ഒന്നാമത്തെയും നാലാമത്തെയും സംഖ്യകളുടെ ആകെത്തുക എത്രയാണ് ?

An amount of Rs 2430 is divided between A,B and C such that if their shares be reduced by Rs 5, Rs 10 and Rs 15 respectively, the remainders shall be in the ratio of 3:4:5. Then find the share of B?

The monthly incomes of two persons are in the ratio of 4 :5 and their monthly expenditures are in the ratio of 7 : 9. If each saves Rs 500 a month, what are their monthly incomes?