Question

E, A, R, T and H each have different age. Only four people are younger than R. There are only two people who are aged between T and A. H is younger than E but elder than A. How many people are elder than E?

• A. Zero
• B. Three
• C. One
• D. Four

Answer 1

Answer:

A. Zero

No one is elder than E (the answer is 0). E is the oldest person in the group.

Let's order the 5 people by age from oldest (1st) to youngest (5th):
1st (Oldest) > 2nd > 3rd > 4th > 5th (Youngest)

Step 1: Place R

• "Only four people are younger than R."

• Since there are 5 people in total, if 4 are younger than R, R must be the oldest.

• Position: R > ___ > ___ > ___ > ___

Step 2: Place T and A

• "There are only two people who are aged between T and A."

• This means there must be exactly two spaces between them (e.g., positions 2 and 5, or positions 1 and 4). Since position 1 is already taken by R, T and A must occupy positions 2 and 5.

• Therefore, the positions look like this: R > (T/A) > ___ > ___ > (A/T)

Step 3: Analyze the relationship between H, E, and A

• "H is younger than E but elder than A."

• This means the relative order must be: E > H > A.

• Since A must have two people (E and H) older than him/her within this sub-group, A cannot be in position 2. A must be at the very bottom in position 5.

• Consequently, T must be in position 2.

• Updated positions: R > T > ___ > ___ > A

Step 4: Fill in the remaining slots for E and H

• We have positions 3 and 4 left open, and we know E > H.

• So, E goes into position 3, and H goes into position 4.

Final Age Order

\text{R (Oldest)} > \text{T} > \text{E} > \text{H} > \text{A (Youngest)}

Looking at our final order, the people elder than E are R and T.