Question

Find:

$\frac{3}{4}+[\frac{3}{4}+\frac{3}{4}\div{(\frac{3}{4}+\frac{3}{4})}]=?$

• A. $$\frac{3}{4}$$
• B. $1$
• C. $2$
• D. $$2\frac{3}{4}$$

Answer 1

Answer:

$2$

Concept Used:

Using the BODMAS principle,

Calculation:

$\frac{3}{4}+[\frac{3}{4}+\frac{3}{4}\div{(\frac{3}{4}+\frac{3}{4})}]=?$

$\frac{3}{4}+[\frac{3}{4}+\frac{3}{4}\div{(\frac{6}{4})}]=?$

$\frac{3}{4}+[\frac{3}{4}+\frac{1}{2}]=?$

$\frac{3}{4}+\frac{3+2}{4}=?$

$\frac{3}{4}+\frac{5}{4}=?$

$\frac{8}{4}=?$

$?=2$