Question

Find the 10th term in the GP: 5, 10, 20, ...

• A. 5120
• B. 1280
• C. 2560
• D. 3200

Answer 1

Answer:

C. 2560

$a=5,r=10/5=2, n = 10$

$a_n=a(r)^{n-1}$

$a_{10}=5(2)^{10-1}$

$=5\times2^{9}$

$=5\times512$

$=2560$