Find the 17th term of an arithmetic progression. If 15th and 21st term of arithmetic progression is 30.5 and 39.5 respectively.A38B35.5C36D33.5Answer: D. 33.5 Read Explanation: T15=a+14d=30.5T_{15} = a + 14d = 30.5T15=a+14d=30.5 ------ (1)T21=a+20d=39.5T_{21} = a + 20d = 39.5T21=a+20d=39.5 ------ (2) Subtract equation 1 from equation 2 6d=96d = 96d=9d=1.5 d = 1.5d=1.5 Put the value of d in equation 1 a+14×1.5=30.5a + 14 \times1.5 = 30.5 a+14×1.5=30.5a=30.5−21a = 30.5 - 21 a=30.5−21a=9.5a = 9.5 a=9.5T17=a+16dT_{17} = a + 16d T17=a+16d =9.5+16×1.5= 9.5 + 16 \times1.5 =9.5+16×1.5=33.5= 33.5=33.5 Read more in App