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Find the compound interest on 10,000 at 10% per annum for 2 years 6 months, compounded annually.

A₹2000

B₹2705

C₹2700

D₹2500

Answer:

B. ₹2705

Read Explanation:

For 2 years 6 months, compounded annually, calculate compound interest for 2 full years first, then simple interest for the remaining 6 months on the amount after 2 years.

Amount after 2 years

A=P(1+R100)nA = P\left(1+\frac{R}{100}\right)^n
A=10000(1+10100)2A = 10000\left(1+\frac{10}{100}\right)^2
=10000(1.1)2= 10000(1.1)^2
=10000×1.21= 10000 \times 1.21
=12100= 12100

Interest for remaining 6 months

SI=12100×10×12100\text{SI} = \frac{12100 \times 10 \times \frac{1}{2}}{100}
=605= 605

Final amount

12705=12100+60512705 = 12100 + 605

Compound Interest


CI=12705−10000=2705\text{CI} = 12705 - 10000 = 2705


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