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Find the compound interest on ₹8,000 at 12% per annum for 3 years 4 months, compounded annually.

A₹3,000

B₹4,000

C₹3,689

D₹3,600

Answer:

C. ₹3,689

Read Explanation:

Principal (P = ₹8000)

Rate (R = 12%) per annum

Time (= 3) years (4) months

Since compounding is annual:

First calculate amount for 3 years:

8000(1+12100)38000\left(1+\frac{12}{100}\right)^3

=8000(1.12)3= 8000(1.12)^3
=8000×1.404928= 8000 \times 1.404928
=₹11239.424= ₹11239.424

For the remaining 4 months, simple interest is added on this amount:

SI=11239.424×12×4100×12SI = \frac{11239.424 \times 12 \times 4}{100 \times 12}

=₹449.57696= ₹449.57696

Total amount:

11239.424+449.57696=₹11689.0009611239.424 + 449.57696 = ₹11689.00096
Compound Interest:

11689.00096−8000=₹3689.0009611689.00096 - 8000 = ₹3689.00096

Therefore, the compound interest is approximately ₹3,689.


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