Question

Find the distance between the parellel lines 3x-4y+7=0 and 3x-4y+5=0.

• A. 2/7
• B. 2/5
• C. 7/5
• D. 5/7

Answer 1

Answer:

B. 2/5

$d=\frac{C_1-C_2|}{\sqrt{A^2+B^2}}$

$=\frac{|7-5|}{\sqrt{3^2+(-4)^2}}$

$=2/5$