Find the greatest number that exactly divides 12, 24 and 40.A3B40C4D2Answer: C. 4 Read Explanation: We need the greatest number that divides 12, 24, and 40 → this is the HCF (GCD).Prime factorization12=(22×3)12 = (2^2 \times 3)12=(22×3)24=(23×3)24 = (2^3 \times 3)24=(23×3)40=(23×5)40 = (2^3 \times 5)40=(23×5)Common factorsCommon prime = (2)Lowest power = (22)(2^2)(22)HCF22=42^2 = 422=4Final Answer:4 Read more in App