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Find the greatest number that exactly divides 12, 24 and 40.

A3

B40

C4

D2

Answer:

C. 4

Read Explanation:

We need the greatest number that divides 12, 24, and 40 → this is the HCF (GCD).

Prime factorization

  • 12=(22×3)12 = (2^2 \times 3)

  • 24=(23×3)24 = (2^3 \times 3)

  • 40=(23×5)40 = (2^3 \times 5)

    Common factors

Common prime = (2)
Lowest power = (22)(2^2)

HCF

  • 22=42^2 = 4
    Final Answer:

4


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