Question

Find the length of the largest rod that can be placed in a room 16m long, 12m broad and $10 \frac{2}{3} m$. high.

• A. 23 m.
• B. 68 m.
• C. $$22\frac{2}{3}m$$
• D. $$22\frac{1}{3}m$$

Answer 1

Answer:

$$22\frac{2}{3}m$$

Length of the largest rod $=\sqrt{l^2+b^2+h^2}$

$=\sqrt{16^2+12^2+(10\frac{2}{3})^2}$

$=\sqrt{16^2+12^2+(\frac{32}{3})^2}$

$=\sqrt{400+\frac{1024}{9}}$

$=\sqrt{\frac{4624}{9}}$

$=\frac{68}{3}$

$=22\frac{2}{3}m$