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Find the number of zeroes at the end of the product of the expression (152×126×504×42)(15^2\times{12^6}\times{50^4}\times{4^2}) ?

A12

B10

C8

D15

Answer:

B. 10

Read Explanation:

Given:

Given Expression: 152 ×\times 126 ×\times 504 ×\times 42

Calculation:

152 ×\times 126 ×\times 504 ×\times 42

⇒ (5×\times 3)2 ×\times (22 ×\times 3)6 ×\times (52 ×\times 2)4 ×\times 24

⇒ 52 ×\times 32 ×\times 212 ×\times 36 ×\times 58 ×\times 24 ×\times 24

⇒ 510 ×\times 220 ×\times 38

⇒ 1010 ×\times 210 ×\times 38

∴ There will be 10 zeroes at the end of the product of the given expression.


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