Challenger App

No.1 PSC Learning App

1M+ Downloads
If the given number 925x85 is divisible by 11, then the smallest value of x is:

A2

B4

C1

D3

Answer:

B. 4

Read Explanation:

Divisibility law of 11: If the difference of the alternating sum of digits of the number is a multiple of 11 (e.g. 2343 is divisible by 11 because 2 - 3 + 4 - 3 = 0, which is a multiple of 11). The number 925x85 is divisible by 11, then 9 – 2 + 5 – x + 8 – 5 = 11 ⇒ ⇒ 15 – x = 11 ⇒ x = 15 – 11 ⇒ x = 4


Related Questions:

4851A53B is divisible by 9 and B is an even number, then find the sum of all the values of A.
The sum of two numbers is 20 and the difference of the squares of those numbers is 80. Find the ratio of the bigger to the smaller numbers?
9 കൊണ്ട് നിശ്ശേഷം ഹരിക്കാവുന്ന സംഖ്യ ഏതാണ്?
What is the least number which should be added to 5560 so the sum is exactly divisible by 2, 3, 5 and 7?
The greatest number of three digit which is divisible by 12, 30, and 50 is: