If the given number 925x85 is divisible by 11, then the smallest value of x is:
A2
B4
C1
D3
Answer:
B. 4
Read Explanation:
Divisibility law of 11: If the difference of the alternating sum of digits of the number is a multiple of 11 (e.g. 2343 is divisible by 11 because 2 - 3 + 4 - 3 = 0, which is a multiple of 11).
The number 925x85 is divisible by 11, then
9 – 2 + 5 – x + 8 – 5 = 11
⇒ ⇒ 15 – x = 11
⇒ x = 15 – 11
⇒ x = 4