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If the given number 925x85 is divisible by 11, then the smallest value of x is:

A2

B4

C1

D3

Answer:

B. 4

Read Explanation:

Divisibility law of 11: If the difference of the alternating sum of digits of the number is a multiple of 11 (e.g. 2343 is divisible by 11 because 2 - 3 + 4 - 3 = 0, which is a multiple of 11). The number 925x85 is divisible by 11, then 9 – 2 + 5 – x + 8 – 5 = 11 ⇒ ⇒ 15 – x = 11 ⇒ x = 15 – 11 ⇒ x = 4


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