Find the smallest square number from among the given options, which is divisible by each of 8, 15 and 20.A3600B6400C14400D4900Answer: A. 3600 Read Explanation: LCM of 8, 15, 20,⇒ 8 = 2×2×22\times{2}\times{2}2×2×2⇒ 15 = 3×53\times{5}3×5⇒ 20 = 2×2×52\times{2}\times{5}2×2×5LCM = 2×2×2×5×32\times{2}\times{2}\times{5}\times{3}2×2×2×5×3To make perfect square then each prime factor has even powersLCM = 2×2×2×2×5×5×3×32\times{2}\times{2}\times{2}\times{5}\times{5}\times{3}\times{3}2×2×2×2×5×5×3×3 = 3600∴ 3600 is the smallest number from among the given options, which is divisible by each of 8, 15 and 20. Read more in App