Question

A number when divided by 25, 30 and 27 leaves a reminder of 1, find the least number which satisfy given condition.

• A. 271
• B. 1351
• C. 451
• D. 1456

Answer 1

Answer:

B. 1351

⇒ Factors of 25 = 5 $\times$ 5

⇒ Factors of 30 = 2 $\times$ 3 $\times$ 5

⇒ Factors of 27 = 3 $\times$ 3 $\times$ 3

⇒ LCM of 25 and 30 and 27 = 5 $\times$ 5 $\times$ 2 $\times$ 3 $\times$ 3 $\times$ 3 = 1350

⇒ Required number = 1350 + 1 = 1351