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Find the sum of first 24 terms of the AP whose nth term is 3 + 2n

A624

B756

C672

D840

Answer:

C. 672

Read Explanation:

an=3+2na_n=3+2n

a1=3+2=5a_1=3+2=5

a2=3+4=7a_2=3+4=7

d=75=2d=7-5=2

Sn=n/2(2a+(n1)dS_n=n/2(2a+(n-1)d

S24=24/2×(2×5+(241)2S_{24}=24/2\times(2\times5+(24-1)2

=12(10+46)=12(10+46)

=12×56=12\times56

=672=672


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