Find the sum of first 24 terms of the AP whose nth term is 3 + 2nA624B756C672D840Answer: C. 672 Read Explanation: an=3+2na_n=3+2nan=3+2na1=3+2=5a_1=3+2=5a1=3+2=5a2=3+4=7a_2=3+4=7a2=3+4=7d=7−5=2d=7-5=2d=7−5=2Sn=n/2(2a+(n−1)dS_n=n/2(2a+(n-1)dSn=n/2(2a+(n−1)dS24=24/2×(2×5+(24−1)2S_{24}=24/2\times(2\times5+(24-1)2S24=24/2×(2×5+(24−1)2=12(10+46)=12(10+46)=12(10+46)=12×56=12\times56=12×56=672=672=672 Read more in App