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Find the value of [(14÷2)×[147+403×(74)][(14 \div 2 ) \times [\frac{14}{7}+\frac{40}{3}\times(7-4)]

A310

B274

C277

D294

Answer:

D. 294

Read Explanation:

Let’s simplify step by step:

[(14÷2)×(147+403×(74))][(14 \div 2) \times \left(\frac{14}{7} + \frac{40}{3} \times (7 - 4)\right)]

  1. (14 \div 2 = 7)

  2. (7 - 4 = 3)

  3. (\frac{40}{3} \times 3 = 40)

  4. (\frac{14}{7} = 2)

So inside the bracket:
2+40=422 + 40 = 42

Now:
7×42=2947 \times 42 = 294

Answer: 294


Related Questions:

Find the value of [(91÷7)×[644+176×(82)]][(91 \div 7)\times[\frac{64}{4}+\frac{17}{6}\times(8-2)]]

(3 + 8) × 4 - 2 × (4 + 7) =
Evaluate: (-9) - (-60) ÷ (-15) + (-3) × 7
Evaluate: 16 + 10 ÷ 5-2×4

Which of the following interchanges of numbers would make the given equation correct?
$6 \times 40 \div 8 + 2 - 5 = 11$