Question

Find the value of Sec (-30^o)+tan(-60^o)

• A. 2
• B. -2
• C. 1
• D. -1

Answer 1

Answer:

B. -2

Sec (-30^o) x tan(-60^o)

Sec(-θ)=Secθ

tan(-θ)=-tanθ

Sec (-30^o) x tan(-60^o)=Sec30^ox(-tan60^o)

$=\frac{2}{\sqrt{3}}\times{-\sqrt{3}}$

$=-2$