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For a thin spherical shell subjected to internal pressure, the ratio of volumetric strain to diametrical strain is.

A5:4

B3:2

C2:1

D3:1

Answer:

D. 3:1

Read Explanation:

For the thin spherical shell, the Hoop strain/longitudinal strain is,

ϵL=ϵh=pd4tE(1μ)\epsilon_{L} = \epsilon_{h} = \frac{pd}{4tE} (1 - \mu)

For the thin spherical shell, the Volumetric strain is,

ϵV=3ϵh=3pd4tE(1μ)\epsilon_{V} = 3\epsilon_{h} = \frac{3pd}{4tE} (1 - \mu)

The ratio of volumetric strain to diametrical strain is

ϵVϵD=ϵVϵh=31\frac{\epsilon_{V}}{\epsilon_{D}} =\frac {\epsilon_{V}}{\epsilon_{h}} =\frac 31


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