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The maximum value of the shear stress in the thin walled cylindrical vessel of diameter d and subjected to internal pressure P is given as

APd/2t

BPd/4t

CPd/8t

DPd/6t

Answer:

B. Pd/4t

Read Explanation:

The maximum shear stress in a thin walled cylindrical vessel of diameter d and internal pressure P is given by tmax = Pd/4t, where t is the thickness of the cylinder. This is obtained by considering the principal stresses and ignoring the third principal stress, which is zero in this case.

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