App Logo

No.1 PSC Learning App

1M+ Downloads
The maximum value of the shear stress in the thin walled cylindrical vessel of diameter d and subjected to internal pressure P is given as

APd/2t

BPd/4t

CPd/8t

DPd/6t

Answer:

B. Pd/4t

Read Explanation:

The maximum shear stress in a thin walled cylindrical vessel of diameter d and internal pressure P is given by tmax = Pd/4t, where t is the thickness of the cylinder. This is obtained by considering the principal stresses and ignoring the third principal stress, which is zero in this case.


Related Questions:

Water is flowing in a pipe of 200 cm diameter under a pressure head of 10000 cm. The thickness of the pipe wall is 0.75 cm. The tensile stress in the pipe wall in MPa is:
Calculate the circumferential stress on a thin-walled pressure tank that experiences an internal pressure of 4 MPa and external pressure of 2.5 MPa. The tank is 50 mm thick with a diameter of 200 mm.
An air vessel has circumferential stress of 267.75 N/mm²; longitudinal stress of 133.875 N/mm²; value of Young's modulus E = 2.1 x 10⁵ N/mm², Poisson's ratio m = 0.3: value of the circumferential strain will be
Lame's equation is used to find stresses in
A thin seamless pipe of diameter 'd' m is carrying fluid under a pressure of 'p' kN/cm². If the maximum stress is not exceed 'ơ' kN/cm², the necessary thickness 't' of metal in cm will be given as