12+35−110=\frac12 +\frac 35 -\frac 1{10} =21+53−101=
A10
B1
C1/10
D2/5
Answer:
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(0.512)13+(0.008)13(0.512)13−(0.008)13=?(0.512)^{\frac{1}{3}} +\frac{ (0.008)^{\frac{1}{3}}}{(0.512)^{\frac{1}{3}}} - (0.008)^{ \frac{1}{3}} =?(0.512)31+(0.512)31(0.008)31−(0.008)31=?