(35+15−310)×3645÷165=(\frac35+\frac15-\frac{3}{10})\times\frac{36}{45}\div\frac{16}{5}=(53+51−103)×4536÷516= A1/20B1/8C32/25D64/125Answer: B. 1/8 Read Explanation: (35+15−310)×3645÷165(\frac35+\frac15-\frac{3}{10})\times\frac{36}{45}\div\frac{16}{5}(53+51−103)×4536÷516=(45−310)×3645÷165=(\frac45-\frac{3}{10})\times\frac{36}{45}\div\frac{16}{5}=(54−103)×4536÷516=12×3645÷165=\frac{1}{2}\times\frac{36}{45}\div\frac{16}{5}=21×4536÷516=1845÷165=\frac{18}{45}\div\frac{16}{5}=4518÷516=25×516=\frac25\times\frac{5}{16}=52×165=18=\frac18=81 Read more in App