dydxtan(y−x.dydx)\frac{dy}{dx}tan(y - x.\frac{dy}{dx}) dxdytan(y−x.dxdy) ആണെങ്കിൽ y Ay-cx = tan cxBy + cx = tan cCy+cx=tan−1cy + cx = tan^{-1}cy+cx=tan−1cDy−cx=tan−1cy-cx=tan{-1}cy−cx=tan−1cAnswer: y−cx=tan−1cy-cx=tan{-1}cy−cx=tan−1c Read Explanation: .Read more in App