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How many diagonals does a hexagon have?

A9

B12

C15

D18

Answer:

A. 9

Read Explanation:

The number of diagonals in an (n)-sided polygon is:

n(n3)2\frac{n(n-3)}{2}

For a hexagon ((n = 6)):

6(63)2\frac{6(6-3)}{2}
=6×32= \frac{6 \times 3}{2}


=9= 9

Answer: 9 diagonals.


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