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How many kilograms of tea, costing ₹250 per kg must be mixed with 25 kg of tea costing ₹400 per kg so that there may be a profit of 10% on selling the mixture at ₹330 per kg?

A45 kg

B40 kg

C60 kg

D50 kg

Answer:

D. 50 kg

Read Explanation:

Selling price (SP) of mixture = ₹330/kg
Profit = 10% ⇒ Cost price (CP) of mixture:

CP=3301.1=300 per kgCP = \frac{330}{1.1} = 300 \text{ per kg}

Use alligation

Cheaper tea = ₹250
Dearer tea = ₹400
Mean price = ₹300

Ratio=(400300):(300250)=100:50=2:1\text{Ratio} = (400 - 300) : (300 - 250) = 100 : 50 = 2 : 1

So,
Cheaper : Dearer = 2 : 1

Given dearer tea = 25 kg

Let cheaper tea = (x)

x25=21\frac{x}{25} = \frac{2}{1}
x=50\Rightarrow x = 50

Final Answer:

50 kg


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