Question

How much sugar at ₹68/kg should be added to 20 kg of tea worth ₹440/kg so that the mixture be worth ₹130/kg?

• A. 100 kg
• B. 120 kg
• C. 80 kg
• D. 110 kg

Answer 1

Answer:

A. 100 kg

Let the quantity of sugar added = (x) kg

Total cost of mixture

• Cost of tea = (20 \times 440 = 8800)

• Cost of sugar = (68x)

  Average price condition

$\frac{8800 + 68x}{20 + x} = 130$
Solve

$8800 + 68x = 130(20 + x)$
$8800 + 68x = 2600 + 130x$
$8800 - 2600 = 130x - 68x$
6200 = 62x
x = 100
$\boxed{100 \text{ kg}}$