If (3x - 6)/x - (4y - 6)/y + (6z + 6)/z = 0, then what is (1/x - 1/y

Challenger App

★

1M+ Downloads

(3x - 6)/x - (4y -6)/y + (6z + 6)/z = 0 ആയാൽ (1/x - 1/y - 1/z) എത്രയാണ്?

B6/5

C5/6

Answer:

(3x - 6)/x - (4y -6)/y + (6z + 6)/z = 0 3 - 6/x - 4 + 6/y + 6 + 6/z = 0 6/x - 6/y - 6/z = 5 1/x - 1/y - 1/z = 5/6

Related Questions:

If x + y = 11, then $(-1)^x + (-1)^y$ is equal to _____

(where x, y are whole numbers).

If a and b are two positive real numbers such that a + b = 20 and ab = 4, then the value of a³ + b³ is:

If $\theta$ is an acute angle, find the denominator A, when $(cosec\theta-cot\theta)^2=\frac{1-cot\theta}{A}$