If (3x−6)/x−(4y−6)/y+(6z+6)/z=0(3x - 6)/x - (4y - 6)/y + (6z + 6)/z = 0(3x−6)/x−(4y−6)/y+(6z+6)/z=0, then what is (1/x−1/y−1/z)?(1/x - 1/y - 1/z)?(1/x−1/y−1/z)? A1B6/5C5/6D0Answer: C. 5/6 Read Explanation: (3x−6)/x−(4y−6)/y+(6z+6)/z=0(3x - 6)/x - (4y -6)/y + (6z + 6)/z = 0 (3x−6)/x−(4y−6)/y+(6z+6)/z=03−6/x−4+6/y+6+6/z=03 - 6/x - 4 + 6/y + 6 + 6/z = 0 3−6/x−4+6/y+6+6/z=0−6/x+6/y+6/z=−6+4−3-6/x + 6/y + 6/z = -6 + 4 - 3−6/x+6/y+6/z=−6+4−3−(6/x−6/y−6/z)=−5-(6/x - 6/y - 6/z) = -5−(6/x−6/y−6/z)=−56/x−6/y−6/z=56/x - 6/y - 6/z = 56/x−6/y−6/z=51/x−1/y−1/z=5/6 1/x - 1/y - 1/z = 5/61/x−1/y−1/z=5/6 Read more in App
