If 4 # 2 = 10 and 6 # 3 = 21, what is 8 # 4?A36B40C44D48Answer: A. 36 Read Explanation: From the given examples:(4 # 2 =4×2+2=8+2=10)= 4 \times 2 + 2 = 8 + 2 = 10)=4×2+2=8+2=10)(6 # 3 =6×3+3=18+3=21)= 6 \times 3 + 3 = 18 + 3 = 21)=6×3+3=18+3=21)So the pattern is:a # b=a×b+b=b(a+1) = a \times b + b = b(a+1)=a×b+b=b(a+1)Now apply it to (8 # 4):8×4+4=32+4=368 \times 4 + 4 = 32 + 4 = 368×4+4=32+4=36 Read more in App