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If 4 # 2 = 10 and 6 # 3 = 21, what is 8 # 4?

A36

B40

C44

D48

Answer:

A. 36

Read Explanation:

From the given examples:

  • (4 # 2 =4×2+2=8+2=10)= 4 \times 2 + 2 = 8 + 2 = 10)

  • (6 # 3 =6×3+3=18+3=21)= 6 \times 3 + 3 = 18 + 3 = 21)

So the pattern is:


a # b=a×b+b=b(a+1) = a \times b + b = b(a+1)

Now apply it to (8 # 4):

8×4+4=32+4=368 \times 4 + 4 = 32 + 4 = 36


Related Questions:

Find the value of

[(42÷7)×(423+194×(84))][(42\div7)\times(\frac{42}{3}+\frac{19}{4}\times(8-4))]

100 + 2 - 20 ÷ 2 എത്ര ?
Evaluate: 2 × {17 - 2 × (9 -5)}
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