Challenger App

No.1 PSC Learning App

★
★
★
★
★
1M+ Downloads
If 4 # 2 = 10 and 6 # 3 = 21, what is 8 # 4?

A36

B40

C44

D48

Answer:

A. 36

Read Explanation:

From the given examples:

  • (4 # 2 =4×2+2=8+2=10)= 4 \times 2 + 2 = 8 + 2 = 10)

  • (6 # 3 =6×3+3=18+3=21)= 6 \times 3 + 3 = 18 + 3 = 21)

So the pattern is:


a # b=a×b+b=b(a+1) = a \times b + b = b(a+1)

Now apply it to (8 # 4):

8×4+4=32+4=368 \times 4 + 4 = 32 + 4 = 36


Related Questions:

56 x 8 / 8 - 9+ 4 =
41 – 30 + (45+7) x 7 =

If '+' means '−', '−' means '÷', '×' means '+', and '÷' means '×', what will be the value of the following expression?

[{(6×9)+(3÷2)}−(7+4)]÷2[\{(6 \times 9) + (3 \div 2)\} - (7 + 4)] \div 2

Find the value of [(23×5)×(6÷6×(18−14)4)][(23 \times 5)\times (6 \div 6 \times \frac{(18-14)}{4})]

Find the value of
[(19×3)×[8÷2×18−144]][(19 \times 3)\times[8 \div 2 \times \frac{18-14}{4}]]